reperiendi

Imaginary time

Posted in General physics by reperiendi on 2009 January 9
Statics (geometric = no time):
s [xlength] x coordinate
m [X] proportionality constant
q(s) [ylength] y coordinate
v(s) = \frac{dq(s)}{ds} [ylength / xlength] slope
T(s) = \int mv(s) dv(s) = mv(s)^2/2 [X ylength^2 / xlength^2] proportional to curvature
V(s) [X ylength^2 / xlength^2] original shape
S = \int (T + V)(s) ds
= \int \left[ \frac{m}{2} \left(\frac{dq(s)}{ds}\right)^2 + V(s) \right] ds
[X ylength^2 / xlength] distortion
Statics (with energy):
s [xlength] x coordinate
F [mass xlength / time^2] force due to stretching spring by dx
q(s) [ylength] y coordinate
v(s) = \frac{dq(s)}{ds} [ylength / xlength] slope at s
T(s) = \int Fv(s) dv(s) = Fv(s)^2/2 [mass ylength^2 / time^2 xlength] stretching energy density
V(s) [mass ylength^2 / time^2 xlength] gravitational energy density
S = \int (T + V)(s) ds
= \int \left[ \frac{F}{2} \left(\frac{dq(s)}{ds}\right)^2 + V(s) \right] ds
[mass ylength^2 / time^2] energy (dS = 0 at equilibrium)
Dynamics (\underline{s \mapsto t, ds \mapsto i\, dt}):
t [time] time
m [mass] mass
q(t) [ylength] y coordinate
v(t) = \frac{dq(t)}{i dt} [ylength / i time] i * velocity
T(t) = mv(t)^2/2 [mass ylength^2 / time^2] kinetic energy
V(t) [mass ylength^2 / time^2] potential energy
S = \int (T + V)(t) (i dt)
= \int \left[ \frac{m}{2} \left(\frac{dq(t)}{i dt}\right)^2 + V(t) \right] (i dt)
= -i \int \left[ \frac{m}{2} \left(\frac{dq(t)}{dt}\right)^2 - V(t) \right] dt
[mass ylength^2 / i time] i * action

See also Toby Bartels‘ sci.physics post.

One Response

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  1. partandwhole said, on 2009 January 12 at 1:31 pm

    I am fascinated. And rueful over my failed phone call this weekend. And massively sleep-deprived after a full-weekend battle with children-borne night terrors and consequent lack of sleep. So: when I call you up (tonight?) can we please talk also about material manifestations, if such there may be, of imaginary time? Does the universe actually manifest this and its manifold derivatives?


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